Concentration of the solution = 1.61 x 10-4 / 0.03 = 5.367 x 10-3

Ahmed AL Balushi
11564611
Ksp post lab
Calculations of post lab: –
1) solution Titration 1: 0.13 mol/L x 7.41 x 10-3 L = 9.63 x 10-4 mol
9.63 x 10-4 x ( 1 / 6 ) = 1.61 x 10-4 mol IO3-
we used a 30 mL in solution
Concentration of the solution
= 1.61 x 10-4 / 0.03 = 5.367 x 10-3
Calcium concentration of solution
= Ca (IO3-) (S ) → Ca2+ (aq) + 2IO- 3 (aq)
5.367 x 10-3 x ½ = 2.684 x 10-3 M of Ca2+
Ksp1
= Ca2+ x IO3- = (2.684 x 10-3) x (5.367 x 10-3)2 = 7.73 x 10-8
solution Titration 2:
0.13 mol/L x 7.76 x 10-3 L = 1.008 x 10-3 mol
= 1.008 x 10-4 x ( 1 / 6 ) = 1.68 x 10-4 mol IO3-
we used a 30 mL in solution
Concentration of the solution
= 1.68 x 10-4 / 0.03 = 5.6 x 10-3
Calcium concentration of solution
= Ca (IO3- ) (S) → Ca2+ ( aq) + 2IO-3 (aq)
4.88 x 10-3 x 1/2 = 2.8 x 10-3 M of Ca2+
Ahmed AL Balushi
11564611
Ksp 2
= Ca2+ x IO3- = 2.8x 10-3 x 5.6 x 10-3 2 = 8.79x 10-8
2) Ksp solution average
= ( 7.73 x 10-8 + 8.79 x 10-8 ) / 2 = 8.26 x 10-8
3) 0.13 mol/L x 6.76×10-3 L = 8.78x 10-4 mol
=8.78x 10-4 x ( 1 / 6 ) = 1.46 x 10-4 mol IO3-
we used a 30 mL in solution
Concentration of the solution
= 1.46 x 10-4 / 0.03 = 4.88x 10-3
0.13 mol/L x 6.32×10-3 L = 8.216 x 10-4 mol
= 8.78x 10-4 x ( 1 / 6 ) = 1.37 x 1 0-4 mol of IO3-
we used a 30 mL in solution
Concentration of the solution
= 1.46 x 10-4 / 0.03 = 4.567 x 10-3
Discussion:
1- a) in this experiment the aim was to determine what is the ksp that the solution of calcium iodate have.
b) We started the experiment by getting the saturated calcium iodate and
start to filter it using funnel and filter paper and pour it into a beaker or flask,
then after filtring I will add 10 mL each in two ernylmer flasks and then I
will add 20 mL and afterwards I added 3 drops of 2% starch solution in each
of the two flasks and finally I added a scoop of potassium iodide, after
preparing the solution I started titrating them with Sodium thiosulfate using
burette to dispense it to the solution. The second part is tottaly the same but I
replaced adding the calcium iodate by the calcium chloride.
Ahmed AL Balushi
11564611

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Author Since: November 30, 2020

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