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Among the pairs of number (x,y) such that 2x-y=12, find the pair for which the sum of the squares is a minimum. I have to solve for y and write the equation in
The sum of the squares equals x^2 + y^2 = x^2 + (2x – 12)^2 because we can substitute y = 2x – 12.
We get a quadratic function f(x) = 5x^2 – 48x + 144, whose minimum is attained at x = 48/(2*5) = 4.8 and equals 28.8. The second number is y = 2x – 12 = – -2.4.
July 20, 2018
UST BE COMPLETELY ORIGINAL WORK Address questions from Case Study attached. Which staffing framework do you recognize in this case study? Explain its characteristics and the advantages to using….